63s^2+32s-63=0

Solution for 63s^2+32s-63=0 equation:

63s^2+32s-63=0

a = 63; b = 32; c = -63;
Δ = b2-4ac
Δ = 322-4·63·(-63)
Δ = 16900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16900}=130$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-130}{2*63}=\frac{-162}{126}
=-1+2/7
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+130}{2*63}=\frac{98}{126}
=7/9
$